Question

A motor cycle is travelling at 30 m/s on a circular road of radius 300 m. Its speed is increasing at the rate of 4 m/s2. Calculate acceleration of the car

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

A motorcycle is traveling at 30 m/s on a circular road of a radius of 300 m. Its speed is increasing at the rate of $4\ m/s^{2}$.

Explanation:

Acceleration (a) of an object is the ratio of its velocity and time.

For an object in a uniform circular motion, the radial acceleration ($a_r$) of that object is the acceleration acting along the radius, directed towards the center which can be expressed as,

$a_r = \frac{v^{2} }{r}$      

Where v is the velocity of the object and r is the radius of the circular path.

From the question,

$r = 300\ m$

$v = 30\ m/s$

Radial acceleration of the motorcycle,

$a_r =\frac{30^{2} }{ 300}} = 3\ m/s^{2}$

Increased acceleration $a_i = 4\ m/s^{2}$

Net acceleration of the motorcycle  $a=\sqrt{a_{r}^{2}+a_{i}^{2}}$

$a = \sqrt{3^{2}+4^{2} } = \sqrt{25} = 5\ m/s^{2}$