A motor cycle moving with a speed of 5 m/s .obtains to an acceleration of 0.2 m/s.calculate the speed of the motor cycle after 10 s ,and the distance travelled by it in this time
Answers
Answered by
2
By using
V=U+AT
we get the speed at 10s is 7m/s and the distance traveled can be found out by using
S=UT+1/2AT^2.
which is 60 meters .
V=U+AT
we get the speed at 10s is 7m/s and the distance traveled can be found out by using
S=UT+1/2AT^2.
which is 60 meters .
Answered by
4
initial speed, u= 5 m/s
acceleration, a= 0.2 m/s
time taken, t= 10s
speed of the motorcycle after 10 s, v = u + at
= 5 + 0.2 × 10
= 5 + 2
v = 7 m/s
distance, s = ut + 1/2 at²
= 5 × 10 + 1/2 × 0.2 × 10 × 10
= 50 + 1/2 × 20
= 50 + 10
s = 60 m
acceleration, a= 0.2 m/s
time taken, t= 10s
speed of the motorcycle after 10 s, v = u + at
= 5 + 0.2 × 10
= 5 + 2
v = 7 m/s
distance, s = ut + 1/2 at²
= 5 × 10 + 1/2 × 0.2 × 10 × 10
= 50 + 1/2 × 20
= 50 + 10
s = 60 m
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