Question

A motor cycle moving with a speed of 5m/s experience an acceleration of 0.2m/s² calculate the speed of motor cycle after 10seconds and the distance travelled by it in this time

Answer 1

Initial speed of a motor cycle = 5 m/s

Acceleration = 0.2 m/s^2

Time for which the acceleration is given to motor cycle = 10 s

Let the speed after 10 seconds be v.

Let the distance traveled in 10 seconds be s.

Now, using first equation of motion:

$v_f = v_i + at$

$\(v = 5 + 0.2 \times 10\)$

v = 7 m/s

Hence, the final speed of the motor cycle is 7 m/s

Now, using second equation of motion to find distance traveled:

$\( s = v_i \times t + \frac{1}{2}\times a \times t^2\)$

$\(s = 5 \times 10 + \frac{1}{2} \times 0.2 \times 10^2\)$

s = 50 + 10

s = 60 m

Hence, the distance traveled is 60 m.