Question

a motor cycle moving with a speed of 5m/s is applied an acceleration of 0.2m/s. calculate the speed of the motor cycle after 10 seconds, and distance travelled by it in this time.

Answer 1

u = 5m/s, a = 0.2$m/s^{2}$, t = 10s
By First Equation of Motion:
v = u+at
v = 5+(0.2*10)
v = 5+2
v = 7m/s

By Second Equation of Motion:
$s=ut+ \frac{1}{2} at^2$
$s=5*10+ \frac{0.2*10*10}{2}$
$s=50+10$
$s=60m$