Question

A motor cycle moving with a speed of 5m/s is subjected to an acceleration of 0.2mpersecondsquare . Find the speed of the motor cycle after 10second and the distance travelled in this time

Answer 1

v1 = 5m/s
v2 = ?m/s
a= 0.2 m/s²
t= 10s

a= v2-v1  /t

0.2 = v2-5  /10
v2=7m/s

d= vt

v= 7m/s
t= 10s
d= 7 x 10 = 70m