A motor cycle moving with a speed of 5m/s is subjected to an acceleration of 0.2mpersecondsquare . Find the speed of the motor cycle after 10second and the distance travelled in this time
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v1 = 5m/s
v2 = ?m/s
a= 0.2 m/s²
t= 10s
a= v2-v1 /t
0.2 = v2-5 /10
v2=7m/s
d= vt
v= 7m/s
t= 10s
d= 7 x 10 = 70m
v2 = ?m/s
a= 0.2 m/s²
t= 10s
a= v2-v1 /t
0.2 = v2-5 /10
v2=7m/s
d= vt
v= 7m/s
t= 10s
d= 7 x 10 = 70m
Daljeetk746:
But can we put the formula
S=ut+1/2atsquare
i don't know that formula so i didn't use it
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