Question

A motor cycle moving with a speed of 5m/s is subjected to an acceleration of 0.2m/s square speed of the motor cycle after 10 second and distance travelled in this time​

Answer 1

Answer:

11 metres

Step-by-step explanation:

Given :

• Initial velocity of the motor cycle = u = 5 m/s

• Acceleration of the motor cycle = a = 0.2 m/s²

• Time taken = t = 10 seconds

To find :

• Distance travelled by the motor cycle = s

Using second equation of motion :

S=ut+½at²

S=5×0.2+½×0.2×100

S=1+½×20

S=1+10

S=11 metres

The total distance travelled in this time period is equal to 11 metres

Answer 2

60 metre

GivEn:-

• Initial Speed of motor cycle = 5m/s

• Acceleration = 0.2 m/s²

• Time taken = 10 second

To find:-

• Final speed of motor cycle = ?

• Distance travelled by motor cycle in that time = ?

Solution:-

★ Using 1st Equation of motion:-

v = u + at

v = 5 + 0.2 × 10

v = 7m/s

★ Now Using 3rd equation of motion:-

v² = u² + 2aS

(7)² = (5)² + 2 × 0.2 × S

49 = 25 + 0.4 × S

49 - 25 = 0.4 × S

24 = 0.4S

S = 24 / 0.4

S = 60m

Hence,

Final speed of motor cycle = 7m/s

And, Distance travelled by motor cycle in that time = 60m

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