A motor cycle moving with a speed of 5m/s is subjected to an acceleration if 0.2m/s². calulate the speed of motor cycle after 10sec and the distance travelled in this time
Answers
Answered by
0
Answer:
Seed after 10 seconds=5+0.2×10=7m per second.
Explanation:
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Answered by
1
Answer:
7m/s 60m
Explanation:
vi=5m/s
a=0.2m/
t=10s
vf=?
as vf=vi+at
vf=5+0.2(10)
vf=5+2
vf=7m/s
s=vit+1/2at^2
S=5(10)+1/2(0.2)(10)^2
S=50+1/2(0.2)(100)
S=50+1/2(20)
S=50+10
S=60m
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