A motor cycle moving with a speed of 5m/s is subjected to an accelaration of 0.2m/square calculate the speed of the motor cycle after 10sec,and the distance travelled in this time
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hii mate!!
U = 5 m/sec
a = 0.2 m/sec ^ 2
t = 10 sec
USING 1ST EQ OF MOTION,
v = u + at
v = 5 + 0.2×10
v = 5 + 2
v = 7 m/sec
FINAL VELOCITY = 7 m/sec
2nd EQ OF MOTION,
s = ut + 1/2 at^2
s = 5 × 10 + 1/2 × 2/10×10×10
s = 50 + 10
s = 60m
DISTANCE = 60 m
HOPE IT HELPS :):):):):):):)
U = 5 m/sec
a = 0.2 m/sec ^ 2
t = 10 sec
USING 1ST EQ OF MOTION,
v = u + at
v = 5 + 0.2×10
v = 5 + 2
v = 7 m/sec
FINAL VELOCITY = 7 m/sec
2nd EQ OF MOTION,
s = ut + 1/2 at^2
s = 5 × 10 + 1/2 × 2/10×10×10
s = 50 + 10
s = 60m
DISTANCE = 60 m
HOPE IT HELPS :):):):):):):)
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