Question

A motor cycle moving with as speed of 5m/s is subjected to an acceleration of 0.2m/s.Cal the speed of the motor cycle after 10s and the distance travelled in this time?

Answer 1

Answer:

60 m

Step by step explanation:

U = 5 m/sec

a = 0.2 m/sec ^ 2

t = 10 sec

USING 1ST EQ OF MOTION,

v = u + at

v = 5 + 0.2×10

v = 5 + 2

v = 7 m/sec

FINAL VELOCITY = 7 m/sec

2nd EQ OF MOTION,

s = ut + 1/2 at^2

s = 5 × 10 + 1/2 × 2/10×10×10

s = 50 + 10

s = 60m

DISTANCE = 60 m

HOPE IT HELPS :):):):):):):)

MARK AS BRAINLIEST

Answer 2

✬ Final Velocity = 7 m/s ✬

✬ Distance = 60 m ✬

Explanation:

Given:

• Initial speed of motorcycle is 5 m/s.
• Acceleration produced by motorcycle is 0.2 m/s².
• Time is 10 seconds.

To Find:

• What is the final velocity and Distance travelled by motorcycle?

Formula to be used:

• a = v – u/t ( for acceleration )
• s = ut + 1/2at²

Solution: Let the final velocity be v.

Finding acceleration

$\implies{\rm }$ 0.2 = v – u/t

$\implies{\rm }$ 0.2 = v – 5/10

$\implies{\rm }$ 0.2(10) = v – 5

$\implies{\rm }$ 2 + 5 = v

$\implies{\rm }$ 7 = v

So , final velocity of or speed of motorcycle after 10 seconds is 7 m/s.

Now, Distance travelled is

$\implies{\rm }$ s = ut + 1/2at²

$\implies{\rm }$ s = 5 $\times$ 10 + 1/2 $\times$ 0.2 $\times$ 10²

$\implies{\rm }$ s = 50 + 0.2/2 $\times$ 100

$\implies{\rm }$ s = 50 + 0.2 $\times$ 50

$\implies{\rm }$ s = 50 + 10

$\implies{\rm }$ s = 60 m

Hence, Distance traveling by the motorcycle after 10 seconds is 60 m.