a motor cycle travelling 20m/s takes 5s to stop. what is the average acceleration
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v= u-at
v=final velocity which is since the vehicle stops.
u= initial velocity = 20m/s
t= time required= 5s
a= 4m/s^2
v=final velocity which is since the vehicle stops.
u= initial velocity = 20m/s
t= time required= 5s
a= 4m/s^2
Answered by
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=). u =20m/s
=) v =0 m/s ( because car comes to rest)
=) t = 5 sec.
so applying
a = (v - u )/t =( 0 - 20)/ 5 =
=. - 20/ 5 = - 4 m/s^2
car retards with 4m/s^2 ans
=) v =0 m/s ( because car comes to rest)
=) t = 5 sec.
so applying
a = (v - u )/t =( 0 - 20)/ 5 =
=. - 20/ 5 = - 4 m/s^2
car retards with 4m/s^2 ans
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