Question

A motor cyclist accelerates uniformly from rest for 3 s and reaches a speed of 9 ms^-1. What will be his acceleration?​

Answer 1

given: time=3sec

V=9m/s

U = 0m/s

a = V-U/T

a = 9-0/3

a=9/3

a =3 m/s^2

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Answer 2

Given :

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 9 m/s
• Time (t) = 3 seconds

To find :

• Acceleration (a)

According to the question,

→ v = u + at

Where,

• v stands for Final velocity
• u stand for Initial velocity
• t stands for Time
• a stands for Acceleration

→ Substituting the values,

→ 9 = 0 + a × 3

→ 9 - 0 = 3a

→ 9 = 3a

→ 9 ÷ 3 = a

→ 3 = a

.°. The acceleration is 3 m/s²..

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More details :-

Acceleration :-

The rate of change of its velocity with time is known as acceleration.

• SI unit is m/s² or meter per second square.

• Acceleration is vector quantity.

• Negative acceleration is also known as retardation.