Question

A motor cyclist along with the machine weighs 260kg While driving at 72km/h, he
stops his machine over a distance of 10 m. find the retarding force of the brakes​

Answer 1

Answer:

Hope it helps you.....(✿◕‿◕✿)

Explanation:

Initial velocity, u = 72 km/h = 72 × 5/18 = 20 m/s

Final velocity, v = 0

Distance for stopping, s = 10m

We know that v^2 - u^2 = 2as

0 - 20^2 = 2 × a × 10

20a = -400

a = -400/20 = -20 m/s^2

So retardation of the motorcycle = 20 m/s^2

Mass = 260 kg

Force = ma = 260 × 25 = 6500 N

∴ Retarding force is 6500 N.

Please mark as brainliest if it really helps you...❤❤❤