Math, asked by KuBo1332, 1 year ago

A motor cyclist goes from mumbai to pune a distance of 192 km, at an average speed of 32 km/h. another man starts from mumbai by car 2(1/2) h after the first and reaches pune half an hour earlier. what is the ratio of the speeds of the motor cycle and the car?

Answers

Answered by ashfaqalimk
4
speed of motor cycle Sm = 32km/h (Sc = d/tc)

distance d = 192km

total time taken for motor cycle tm = d/Sc = 192/32 = 6

total time taken for car tc = 6 - (2.5+.5) = 3

speed of car Sc = d/tc = 192/3

Sm = 32 =192/6

The ratio Sm/Sc = (192/6) / (192/3) = 1/2


Answered by mahatatushar25
3

Answer:

1 : 2

Step-by-step explanation:

D = 192

Speed = 32km/h

Time (1st Man) = D / Speed

        = 192 / 32

        = 6 h

Time (2nd Man) = (6 - 3) h

                          = 3 h

Time Ratio = 6 : 3 = 2 : 1

Speed Ratio = 1 : 2

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