A motor cyclist goes from mumbai to pune a distance of 192 km, at an average speed of 32 km/h. another man starts from mumbai by car 2(1/2) h after the first and reaches pune half an hour earlier. what is the ratio of the speeds of the motor cycle and the car?
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Answered by
4
speed of motor cycle Sm = 32km/h (Sc = d/tc)
distance d = 192km
total time taken for motor cycle tm = d/Sc = 192/32 = 6
total time taken for car tc = 6 - (2.5+.5) = 3
speed of car Sc = d/tc = 192/3
Sm = 32 =192/6
The ratio Sm/Sc = (192/6) / (192/3) = 1/2
distance d = 192km
total time taken for motor cycle tm = d/Sc = 192/32 = 6
total time taken for car tc = 6 - (2.5+.5) = 3
speed of car Sc = d/tc = 192/3
Sm = 32 =192/6
The ratio Sm/Sc = (192/6) / (192/3) = 1/2
Answered by
3
Answer:
1 : 2
Step-by-step explanation:
D = 192
Speed = 32km/h
Time (1st Man) = D / Speed
= 192 / 32
= 6 h
Time (2nd Man) = (6 - 3) h
= 3 h
Time Ratio = 6 : 3 = 2 : 1
Speed Ratio = 1 : 2
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