Question

a motor cyclists is to undertake horizontally Circular tack. For r=5 m, static friction=04,
g=10 m/s2. then frequency necessary to perform this stunt.​

Answer 1

Given Data:

• Cylindrical Wall of a well of inner radius (r) = 5 m.

• Coefficient of static friction between the Tyres and the Circular tack (μ)=04

• Acceleration due to gravity(g)$=10m/s^2$

To find:

            The frequency (n) necessary to perform the stunt.

solution:

         We need to find the minimum speed

$V_{minimum}=\sqrt{\frac{radius(gravity)}{static friction} } \\\\V_{minimum=\sqrt{\frac{5X10}{4} }$

$V_{minimum=\sqrt{\frac{50}{4} }$

$V_{minimum}=\sqrt{12.5} \\V_{minimum}=3.53m/s$

Hence ,the minimum speed of the motorcyclist will be $3.53m/s$m/s. Now, let's find the frequency (n) necessary to perform the stunt.

v=rω

Where, v is the linear velocity , r is the radius and ω is the angular speed/velocity.

we know that ,ω=2πn

  v=r×2πn

 v=5×2×3.14×n

v=10×3.14×n

3.53=31.4n

3.53/31.4=n

0.1124=n

n≈0.12 rev/sec