Question

a motor cyclists moves with an acceleration of 5 ms^-2 along a horizontal road against a total resistance of 120N. The total mass of the rider and the motor cycle is 400kg. Find the driving force provided by the engine.​

Answer 1

Answer:

F = ma

$F_{net}$ = 400 x 5 = 2000 N

This is the net force applied on the cyclist as he moves along the road.

The driving force F is in the forward direction while the resistance is in the opposite direction.

We can clearly say that,

$F_{net} = F_{driving} - F_{resistance}$

2000 = $F_{driving} - 120$

$F_{driving} = 2000 + 120$

$F_{driving}$ = 2120 N

The driving force provided by the engine is 2120 N.

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