Question

A motor of 100 H.P. moves a load with a uniform speed of 72
km/hr. The forward thrust applied by the engine on the car
is
(a) 1111 N (b) 3550 N
(c) 2222 N (d) 3730 N

Answer 1

Power ☞

$\sf\blue{100 \times 746 \: w}$

⟹ $\sf\pink{74600w}$

Velocity ☞

$\sf\orange{72 \: km \: hr}$

⟹ $\sf\green{72 \times \frac{5}{18} = 20ms}$

Power = Force × Velocity

Force = Power/Velocity

$\sf\red{\frac{74600}{20}}$ = $\sf\red{3730N}$

So your answer is Option D.