A motor of 100 hp moves with a uniform speed 72km/h. the forward thrust applied by the engine on the car is?
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Given conditions ⇒
Power = 100 hp.
= 100 × 746 W.
= 7.46 × 10⁴ W.
Velocity = 72 km/hr. = 72 × 5/18
= 4 × 5 = 20 m/s.
Using the Formula,
Power = Force × Velocity
⇒ Force = Power/Velocity
∴ Force = 7.46 × 10⁴/20
Force = 3.73 × 10³ N .
Hence, the Forward Thrust on the Engine is 3.73 × 10³ N.
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