Question

A motor of half hp runs at 500 rpm . If the efficiency of the motor is 60 % then calculate the work done by the motor in one rotation .

Answer 1

Explanation:

Given A motor of half hp runs at 500 rpm . If the efficiency of the motor is 60 % then calculate the work done by the motor in one rotation .

• Power is 1/2 hp = 746 / 2 = 373 W
• Since efficiency of motor is 60 %  
• The power used in doing work is 60% of 373 W so,
• P = 373 x 60/100  
• P = 223.8 W
• Angular velocity of the motor ω = 500 rpm
• So ω = 500 x 2π / 60 rad/s
• So ω = 16.6 π rad/s
• Let the torque be τ
• So P = τω
• So τ = P / ω
•        = 223.8 / 16.6 π
• Now work done in 1 rotation = τ x 2π
•                                                 = 223 / 16.6 π x 2π
•                                                = 26.86 J
• Reference link will be
• https://brainly.in/question/2456983

Answer 2

Answer:

26.85J

Explanation:

n=500rpm

=

$\frac{500}{60}$

=

$\frac{25}{3}$

rps

t=3/25

W=pt

=60/100×373×3/25

=26.85J