Question

A motor running from a 220-V line is lifting a mass of 35 kg at a constant speed of 6.0 m/s. Assuming 100% efficiency,
the current required is

Answer 1

Answer:

The current required by the motor is 9.4 A.

Explanation:

To find the current required by the motor, we need to use the formula:

Power (P) = Current (I) x Voltage (V)

We know the voltage is 220 V, and the power (P) is equal to the force (F) applied by the motor multiplied by the velocity (v) at which the mass is lifted:

P = F x v

The force F is equal to the weight of the mass, which is:

F = m x g

Substituting values of m and g, we get:

F = 35 kg x 9.8 m/s² = 343 N

P = F x v = 343 N x 6.0 m/s = 2058 W

Now we can use the formula to find the current (I),

I = P / V = 2058 W / 220 V = 9.4 A.

Power

• power is defined as the rate at which work is done or energy is transferred. Power is a scalar quantity.
• Mathematically, power (P) is defined as the amount of work (W) done or energy (E) transferred per unit time (t): P = W/t or P = E/t.

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