Physics, asked by jahnavik1318, 30 days ago

A motor takes an input of 25 kW from a 250 V supply. Find the current flowing through the
motor. If the motor is in operation for one hour each day on an average, what is the energy
consumed in kWh in one month. If electrical energy costs at Rs 1 per kWh, what is the
monthly bill?

Answers

Answered by NewGeneEinstein
0

Answer:-

  • Power=P=25Kw
  • Voltage=V=250V
  • Current=I=?

We know that

\boxed{\sf P=VI}

\\ \qquad\quad\sf\longmapsto I=\dfrac{P}{V}

\\ \qquad\quad\sf\longmapsto I=\dfrac{25}{250}

\\ \qquad\quad\sf\longmapsto I=0.1A

Now

  • Cost per kwh=Rs 1

\\ \qquad\quad\sf\longmapsto Cost\:for\:25kwh=25\times 1=25 Rupees

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