Question

A motor takes an input of 25kW from a 250V supply. Find current flowing through the motor. If the motor is in operation for one hour each day on an average, what is the energy consumed in kWh in 1 month . If electrical energy costs Rs.1 per kWh. what is the monthly bill?​

Answer 1

Here,

Power, P = 25 kW = 25000 W

Voltage, V = 250 v

Time, t = 1 hr

rate of energy = ₹1/kWh

Current, I = ?

monthly bill = ?

Now,

P = VI

⇒ 25000 = 250 × I

⇒ I = 25000 ÷ 250

⇒ I = 100 A

Energy consumed in 1 day = P×t = 25 kW × 1hr

= 25 kWh

Energy consumed in 1 month = 30 × 25 kWh

= 750 kWh

Energy bill = ₹1/kWh × 750 kWh = ₹750