Question

A motor with a resistance of 32Ω is connected to a voltage source. Four amps of current flows in the
circuit. What is the voltage of the source? plz dont give wrong answer​

Answer 1

Answer:

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Explanation:

V = I · R = (3.8 Amperes) · (32 ohms) = 121.6 volts

Answer 2

Explanation:

Formula to find it.......

V=IxR

so

V=4(a)x32 ohm

v= 128 volt