Question

A motorbike initially moves at 18 km/h, accelerates at the rate of 5 m/s^2 for 5 seconds. Calculate the distance covered by it from start and its velocity.

Answer 1

Given :-

➜ Initial velocity, u = 18 km/h or 5 m/s

➜ Acceleration throughout the time, a = 5 m/s²

➜ Time taken, t = 5 s

To Find :-

➜ Final velocity of motorbike

➜ Distance travelled in this time

Solution :-

We know,

⇒ v = u + at

Substituting values,

⇒ v = 5 + 5×5

⇒ v = 5 + 25

⇒ v = 30 m/s

So, we found final velocity to be 30 m/s

Also,

⇒ 2as = v² - u²

Substituting values,

⇒ 2×5×s = 30² - 5²

⇒ 10s = 900 - 25

⇒ 10s = 875

⇒ s = 87.5 m

Hence, The final velocity of the motorbike is 30 m/s while distance travelled by the motorbike is 87.5 m.