Question

A motorbike initially moving at 18 km/hr accelerate at a rate of 5 m/s² for 5 seconds.
Calculate   1) the distance covered by it from the start 
                 2) the final velocity

Answer 1

u=18 km/hr=18*(1000/3600)
  =5 m/s
a= 5 m/s^2
t= 5 sec
1)Solution
s=?
Using 2 equation of motion which is s=ut+1/2 at^2 we get
s= 5*5+ 1/2*5*25
  =25+125/2
  =(50+125)/2
  =175/2
  = 87.5 m
2)Solution
v=?
Using 1 equation of motion which is v= u+at we get
v=5+5*5
v=5+25
v=30
Hence
The distance travelled = 87.5 m
The final velocity = 30m/sec

Answer 2

Answer:

87.5 m and 30m/s............