a motorbike initially moving at 18 km per hour accelerates at the rate of 5 metre per second square for 5 seconds calculate the distance covered by it from start the final velocity
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Explanation:
We have given that u=18km/hour=5metre/second.
a(acceleration)=5metre/second square.
t=5second
now we know that,
v=u+at
v=(5+5×5)metre/second
v=30metre/second
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