Question

a motorbike initially moving at 18 km per hour accelerates at the rate of 5 metre per second square for 5 seconds calculate the distance covered by it from start the final velocity ​

Answer 1

Explanation:

We have given that u=18km/hour=5metre/second.

a(acceleration)=5metre/second square.

t=5second

now we know that,

v=u+at

v=(5+5×5)metre/second

v=30metre/second