A motorbike is running at a velocity of 72kmh-1.On applying brakes, it is brought to rest in 2s.What is
the distance covered by the motorbike before coming to rest? Presume that acceleration produced by
brakes is uniform throughout.
10m
20m
5m
40m
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Given that,
Initial speed of the motorcycle, u = 72 km/h = 20 m/s
It brought to rest, v = 0
Time, t = 2 s
Let a is the acceleration of the motorcycle. It is given by the formula as :
Let d is the distance covered by the motorcycle in these 2 second. It can be calculated using second equation of motion as :
So, the distance covered by the motorcycle in these 2 second is 20 meters. Hence, this is the required solution.
Kinematics
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