Question

a motorbike joints a motorway traveling at 10m/s and increases speed to 30m/s with a constant acceleration of 1.25m/s square along the straight road. How much time does this take and how far does the bike travelled in that time??

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Answer 1

initial velocity = 10 m/s

final velocity = 30 m/s

acceleration = 1.25 m/s²

time × acceleration = final velocity - initial velocity

⇒ $time = \frac{final velocity - initial velocity}{acceleration}$

⇒ time = (30-10)/1.25

⇒ time = 20/1.25

⇒ time = 16 seconds

for distance,

$s=ut+\frac{1}{2} at^{2}$

⇒ s = (10 × 16) + (1/2 × 1.25 × 16 × 16)

⇒ s = 160 + 160

⇒ s = 320 m

therefore, time = 16 seconds and distance = 320 m

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