Math, asked by burningphoenix97, 5 months ago

A motorbike leaves City-1 at 11 am and moves towards City-2 at a uniform speed. A car leaves City-2 at 1 pm same day and moves towards City-1 at same uniform speed as
that of the motorbike. They meet each other at 4 pm. What would be meeting time if the motor biker had driven at 20% higher speed and the car driver had driven at 20%
lower speed (assume that their starting time remains unchanged)?
3:40 PM
3:48 PM
3:52 PM
3:56 PM​

Answers

Answered by motiur63
0

Guess our time is 3.52PM

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