A motorbike leaves point A at 1 pm and moves towards point B at a uniform speed. A car leaves point B at 2 pm and moves towards point A at a uniform speed which is double that of the motorbike. They meet at 3:40 pm at a point which is 168 km away from A. What is the distance, in km, between A and B ?
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Given that motorbike leaves point A at 1 pm and moves towards point B.
Car leaves at point B at 2 pm and moves towards point A where the speed is equal to double that of motor bike.
Both meet at 3.40 pm at a point which is 168 km away from A
Bike travelled from 1 to 3:40 pm = 8/3 hrs at a speed of x
Car travelled from 2 to 3:40 pm = 5/3 hrs at a speed of 2x
8/3 × x = 168
5/3 × 2x = ?
This is in the ratio 8 : 10 = 168 : ?
⟹ 4 : 5 = 168 : ?
⟹ 168×5/8 = 210
A : B = 4 : 5 = 168 : 210
The distance, in km, between A and B is 168 + 210 = 378 kms
Answer
378 km
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