A motorbike starting from rest on a lake accerlerates in a straight line at a constant rate of 3.0 m s-2 for 8.0 s. how far does the boat travel during this time
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U= 0
V= U + at
= 0 + 8*3 = 24 m/s
S = ut + 1/2*a*t*t
= 0+36
= 36 m
Answered by
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Explanation:
Given, initial velocity of boat is: u=0
Acceleration is: a=3 ms^2
Time is: t=8 s
Using second equation of motion:
s=ut+ 1/2at^2
s=0×8+ 1/2×3×8^2 =96 m.
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