A motorboat covers a distance of 16 km upstream and 24km downstream in 6 hours. In the
COR
same time it covers a distance of 12 km upstream and 36km downstream. Find the speed of
the boat in still water and that of the stream.
Answers
Let speed of the boat in still water = x km/hr, and
Speed of the current = y km/hr
Downstream speed = (x+y) km/hr
Upstream speed = (x - y) km/hr
24u + 16v = 6
Or, 12u + 8v = 3... (3)
36u + 12v = 6
Or, 6u + 2v = 1... (4)
Multiplying (4) by 4, we get,
24u + 8v = 4… (5)
Subtracting (3) by (5), we get,
12u = 1
Putting the value of u in (4), we get, v =
Thus, speed of the boat upstream = 4 km/hr
Speed of the boat downstream = 12 km/hr
hope it helps you✨
Answer:
Let speed of the boat in still water = x km/hr, and
Speed of the current = y km/hr
Downstream speed = (x+y) km/hr
Upstream speed = (x - y) km/hr
t = \frac{d}{s}t=
s
d
\frac{24}{x + y} + \frac{16}{x - y} = 6...(1)
x+y
24
+
x−y
16
=6...(1)
\frac{36}{x + y} + \frac{12}{x - y} = 6...(2)
x+y
36
+
x−y
12
=6...(2)
putting \: \frac{1}{x + y} = u \: and \frac{1}{x - y} = v \: the \: equations \: become = >putting
x+y
1
=uand
x−y
1
=vtheequationsbecome=>
24u + 16v = 6
Or, 12u + 8v = 3... (3)
36u + 12v = 6
Or, 6u + 2v = 1... (4)
Multiplying (4) by 4, we get,
24u + 8v = 4… (5)
Subtracting (3) by (5), we get,
12u = 1
= > u = \frac{1}{12}=>u=
12
1
Putting the value of u in (4), we get, v =
\frac{1}{4}
4
1
\frac{1}{x + y} = \frac{1}{12} \: and \: \frac{1}{x - y} = \frac{1}{4}
x+y
1
=
12
1
and
x−y
1
=
4
1
x + y = 12 \: and \: x - y = 4x+y=12andx−y=4
Thus, speed of the boat upstream = 4 km/hr
Speed of the boat downstream = 12 km/hr
Step-by-step explanation:
thanku