Math, asked by Paul337, 4 months ago

A motorboat covers a distance of 16km upstream and 24km downstream

in 6 hours. In the same time it covers a distance of 12 km upstream and

36km downstream. Find the speed of the boat in still water and that of the

stream.​

Answers

Answered by shahkhushee700
22

Step-by-step explanation:

speed of the boat in still water =x km/hr, and

Speed of the current =y km/hr

Downstream speed =(x+y) km/hr

Upstream speed =(x−y) km/hr

T=

S

D

x+y

24

+

x−y

16

=6 .......(1)

x+y

36

+

x−y

12

=6 .......(2)

Put

x+y

1

=u and

x−y

1

=v the above equation becomes,

24u+16v=6

Or, 12u+8v=3 ... (3)

36u+12v=6

Or, 6u+2v=1 ... (4)

Multiplying (4) by 4, we get,

24u+8v=4v … (5)

Subtracting (3) by (5), we get,

12u=1

⇒u=

12

1

Putting the value of u in (4), we get, v=

4

1

x+y

1

=

12

1

and

x−y

1

=

4

1

⇒x+y=12 and x−y=4

Thus, speed of the boat upstream =4 km/hr

Speed of the boat downstream =12 km/hr

Answered by sarthak647
48

Answer:

Mark as the brainliest because this is the original and this is the correct answer. So here we go ...

Step-by-step explanation:

Let speed of the boat in still water =x km/hr, and

Speed of the current =y km/hr

Downstream speed =(x+y) km/hr

Upstream speed =(x−y) km/hr

T=  S /D

​x+y /24  +  x−y /16=6          .......(1)

x+y/36  +  x−y /12 =6          .......(2)

Put  

x+y  =1/u and  

x−y  =1/v the above equation becomes,

24u+16v=6

Or, 12u+8v=3               ... (3)

36u+12v=6

Or, 6u+2v=1                ... (4)

Multiplying (4) by 4, we get,

24u+8v=4v                  … (5)

Subtracting (3) by (5), we get,

12u=1

⇒u=  1 /12

Putting the value of u in (4), we get, v=  1 /4

⇒x+y=12 and x−y=4

2x = 16 =>x = 8

and 8 + y = 12 => y = 4

Thus, speed of the boat in still water =8 km/hr

Speed of the boat in stream = 4 km/hr

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