Question

A motorboat of 200kg starts from rest on a lake and accelerates at rate of 6m/s2 . What will be the force exerted on engine

Answer 1

Answer:

Initial velocity of the motorboat     u=0

Acceleration of the boat   a=3.0  ms  

−2

 

Time   t=8 s

Let the distance covered during this time be  d

Using 2nd equation of motion, d=ut+  

2

1

​  

at  

2

 

d=(0)×8+  

2

1

​  

×(3)×8  

2

 

d=96 m

hope it helps u

Explanation:

Answer 2

Answer:

Force = 1200N

Explanation:

m = 200kg

a = 6 m/s²

F = ma

F = 200×6

F = 1200N = Ans.

Hope it helps you...

Thank you...