Question

A motorboat starting from rest on a lake accelerate in a straight line at constant rate of 3 m/ s 8.0 second. How far does the boat travel during this time
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Answer 1

Answer:

Hey Mate!!

Given,

u = 0 m/s

a = 3 m/s^2

t = 8 s

$s = ut + \frac{1}{2} a {t}^{2} \\ = > (0)(8) + \frac{1}{2} (3) {(8)}^{2} \\ = > 0 + \frac{1}{2} \times 3 \times 64 \\ = > 32 \times 3 \\ = > \boxed{ \bold{96 \: metres}}$

Answer 2

Answer:

96 m

Explanation:

Given :

Initial velocity u = 0 m / sec

Acceleration a = 3 m / sec²

Time t = 8 sec

We are asked to find distance s :

Using second equation of motion :

s = u t + 1 / 2 a t²

Putting values here we get :

= > s = 0 × 8 + 1 / 2 × 3 × 8² m

= > s = 0 + 1 / 2 × 3 × 64 m

= > s = 3 × 32 m

= > s = 96 m

Therefore , motorboat distance 96 m distance!