Question

A motorboat starting from rest on a lake accelerate in a straight line at a constant rate of 3.0m s-2 for 8.0s how far does the boat travel during this time?

Answer 1

$s = ut + \frac{1}{2} a {t}^{2}$
Here u=0 as the boat initially at rest
acceleration,. a= 3 m/s²
and time t=8s
so Displacement S= 0+ 1/2 × 3 ×8² = 96 m

Answer 2

Answer:given, v=0 a=3m/s2 u=8s.

We know,

Explanation:s=ut+1/2at2

=1/2+at2. =1/2*3*8*8m. =96m... hope it will help you..... If u have any doubt on it.... Ask for it... I'm ur helping ✋.. Plz like n comment