a motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0 ms-² for 8.0 s. how far does the boat travel during this time?
Answers
Given:
- Initial velocity,u = 0 m/s
- Acceleration,a = 3.0 m/s²
- Time taken, t = 8.0 s
To be calculated:
Calculate the distance travelled by boat?
Formula used:
s = ut + 1/2 at²
Solution:
According to the second equation of motion, we have :
s = ut + 1/2 at²
★ Substituting the values in the second equation of motion, we get
s = 0 × 8.0 + 1/2 × 3 × ( 8.0 )²
s = 0 + 1/2 × 3 × 64
s = 3 × 32
s = 96 m
Thus, the boat travels a distance of 96 metres.
Step-by-step explanation:
given that a motorboat starts from rest on a lake. which means the initial velocity is zero let the initial velocity be (u). so u=0. let the final velocity process in by the boat after 8 seconds be (v) units. we haveto find the distance travelled by the body with an acceleration of 3 metre per second square at a constant rate for 8 seconds.let the distance travelled a be (s) units. we can use the kinematic equation as [s= ut +1/2a t square]•s=(0)(8)+1/2(3)(8)(8) . therefore s=0+(3)(4)(8)= 96 meters. therefore the distance travelled by the boat is 96 metres.