Question

A motorboat starting from rest on a lake accelerates in a straight line of a constant rate of 3.0ms-square for 8.0. How far does the boat travel during this time?​

Answer 1

Answer:

Given Initial velocity of motorboat, u = 0

Acceleration of motor boat, a=3.0m s-2

Time under consideration, t = 8.0s

We know that Distance, S=ut + (1/2)at2

Therefore, The distance travel by motor boat = 0 —8 + (1/2)3.0 x 8 2

= (1/2) x 3 x 8 x 8 m

= 96 m

Explanation:

hope it is helpful

Answer 2

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.