Question

A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3 ms

–2 for 8 s. How far

does the boat travel during this time?​

Answer 1

hlo mate here is ur ans...

Given Initial velocity of motorboat, u = 0

Acceleration of motor boat, a=3.0m s-2

Time under consideration, t = 8.0s

We know that Distance, S=ut + (1/2)at2

Therefore, The distance travel by motor boat = 0 —8 + (1/2)3.0 x 8 2

= (1/2) x 3 x 8 x 8 m

= 96 m

                 (OR)

Answer

Given, initial velocity of boat is: u=0

Acceleration is: a=3 ms−2

Time is: t=8 s

Using second equation of motion:s=ut+1​/2at^2

s=0×8+1/2​×3×82=96 m

HOPE THIS HELPS UH DEAR :)

pls mark as brainliest..........

Answer 2

Given :

• Acceleration of boat = 3 m/s²
• Time = 8 seconds

To Find :

• The distance travelled by the boat during that time

Solution :

• From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.