a motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3 ms-2 for 8s. how far the boat travel during the time
Answers
Given :-
A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3 m/s² for 8 seconds .
Required to find :-
- Distance travelled during the time ?
Equations used :-
v = u + at
v² - u² = 2as
Solution :-
Given data :-
A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3 m/s² for 8 seconds .
we need to find the distance travelled in that given time ?
So,
From the given information we can conclude that ;
Initial velocity of the motorboat ( u ) = 0 m/s
Acceleration ( a ) = 3 m/s²
Time ( t ) = 8 seconds
using the 1st equation of motion
☛ v = u + at
☛ v = 0 + 3 x 8
☛ v = 0 + 24
☛ v = 24 m/s
Hence,
Final velocity of the motorboat ( v ) = 24 m/s
Using the equation of motion
i.e.
☛ v² - u² = 2as
☛ ( 24 )² - ( 0 )² = 2 x 3 x s
☛ 576 - 0 = 2 x 3s
☛ 576 = 6s
☛ 6s = 576
☛ s = 576/6
☛ s = 96 meters
As we know that
s = displacement
However,
Since, according to the condition we can take displacement in terms of distance but we can't take distance in terms of displacement .
So,
Distance travelled by the motorboat ( s ) = 96 meters
Additional Information :-
These equations of motion are only applicable when the acceleration of the body is constant .
The other equation of motion is ;
- s = ut + ½ at²
Speed is a scalar quantity .
Velocity is a vector quantity .
Given,
u=0,
a=3m/s²,
t=8s
From the formula v=u+at
v=0+8×3
v=24m/s
From the formula s=ut+1/2at²
s=0×8+1/2×3×8²
s=0+3×32
s=96m
HOPE IT HELPS YOU....