Question

A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 2 metre per second square for 6 s. How far does the boat travel during this time?

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 0 m/s (As boat starts from rest)

Acceleration, a = 2 m/s²

Time taken, t = 6 seconds

To Find,

Distance covered, s = ?

At first we have to find final velocity,

According to the 1st equation of motion,

We know that,

v = u + at

⇒ v = 0 + 2 × 6

⇒ v = 12 m/s.

Here, the final velocity is 12 m/s.

Now, the distance covered,

According to the 3rd equation of motion,

We know that,

v² - u² = 2as

⇒ (12)² - (0)² = 2 × 2 × s

⇒ 144 = 4s

⇒ 144/4 = s

⇒ s = 36 m.

Hence, the distance covered by boat is 36 m.

Answer 2

⭐ Question ⭐

A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 2 metre per second square for 6 s. How far does the boat travel during this time?

⭐ Answer ⭐

Given that

Initial velocity of motorboat, u = 0

Acceleration of motorboat, a=2ms-2

Time under consideration, or time taken t = 6 s

Formula

We know the equation of motion

Distance, s=ut + (1/2)at²—————-(i)

Substituting the given and known values in equation (i) we get,

s= o (6) + 1/2 (2) (6)²

= 1/2 (2) (36)

= 2 (18)

= 36

Therefore, The distance travel by motorboat = 36 m