Question

A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 2 metre per second square for 6 s. How far does the boat travel during this time?​

Answer 1

Answer:

Given,

a=2m/s^-2

t=6s

:. v= at

    =2.6=12 m/s

we know,

s=vt

=12.6=72m

the boat travels 72 m during this time.

hope it’ll help u . Pls mark me as the brainliest.

Answer 2

${\huge{\underline{\rm{\blue{GIVEN}}}}}$

• $\rm\blue{Initial\:Velocity (u) = 0m/s}$

• $\rm\red{Acceleration = 2m/s^{-2}}$

• $\rm\green{Time\: Given = 6s.}$

${\huge{\underline{\rm{\blue{TO\: FIND}}}}}$

• The Distance travelled During this time.

${\huge{\underline{\rm{\blue{FORMULAE\: USED}}}}}$

• ${\boxed{\rm{\blue{S= ut+\dfrac{1}{2}\times{a}\times{(t)^2}}}}}$

Where,

S = Distance

u = initial velocity

t = Time

a = Acceleration

Now,

$\implies\rm\red{S= ut+\dfrac{1}{2}\times{a}\times{(t)^2}}$

$\implies\rm\red{ S = 0\times{6}+\dfrac{1}{\cancel{2}}\times{\cancel{2}}\times{36}}$

$\implies\rm\red{ S = 0 + 36}$

$\implies\rm\red { S = 36m}$

Thus, The distance travelled by motorboat is 36m.

MORE FORMULAES :-

• ${\huge{\boxed{\blue{v= u+ at}}}}$

• ${\huge{\boxed{\blue{v^2-u^2 = 2as}}}}$