Question

A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0m/s for 8.0s. How far does the boat travel during this time?​

Answer 1

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Given:-

Intial velocity of boat(u) = 0

Acceleration (a) = 3.0m/s

Time (t) = 8sec

Distance covered (s) = ?

We know that $s = ut + \frac{1}{2} {at}^{2}$

$s = 0 \times 8 + \frac{1}{2} \times 3 \times ( {8})^{2}$

= $0 + \frac{1}{2} \times 3 \times 64 = 96m$

$s = 96m$

Ans:- Therefore, distance covered = 96m

Answer 2

equation of kinematics: motion :

         s = u t + 1/2 a t²

   here u = 0 m/sec  a = 3.0 m/sec/sec    t = 8.0 sec

           s  = 0 * 8.0 + 1/2 * 3 m/sec² * (8.0 sec)²

      distance travelled in 8 sec = 96 meters