Question

A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3 ms-2

for 8 seconds . How far does the boat travel during this time?​

Answer 1

Answer:

s=ut+1/2at^2

so, s=0(8sec)+1/2x3m/sec^2x8(sec)^2

therefore, s=3x4m

this implies s=12m

Explanation:

Here s=distance travelled by the boat

a=acceleration of the boat

u =initial velocity of the boat=0

since the boat is at rest

using the formula of linear motion we get the s=12m

Answer 2

GIVEN:-

$\large\sf{Initial\:velocity\:of\:boat(u)=0}$

$\large\sf{Acceleration(a)=3.0m/s}$

$\large\sf{Time(t)=8s}$

⠀⠀⠀

$\large\sf\red{Distance\:covered(s)=?}$

$\large\sf\red{We\:know,}$

$\longrightarrow$$\large\sf\red{s = ut + \frac{1}{2} {at}^{2} }$

$\longrightarrow$$\large\sf\red{s = 0 \times 8 + \frac{1}{2} \times 3 \times {(8)}^{2} }$

$\longrightarrow$$\large\sf\red{0+\frac{1}{2}×3×64}$

$\longrightarrow$$\large\sf\red{96m}$