Physics, asked by shnayasheikh, 1 year ago

A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0 m s-2 for 8.0s how far does the boat travel during this time?
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Answers

Answered by Aryan2524
4
u = 0 m/s(rest)
a = 3m/s^2
t = 8 s
first,
v = u+ at
v = 0 + 3*8
v = 24m/s
Now,
s = ut + 1/2at^2
s = 0 + 1/2 * 3*64
s = 96m
plz thnx and mark as brainliest
Answered by Deepsbhargav
4
hey friend!!!!!

your answer is "96m"

Explanation =>
____________

Initial velocity, u = 0 (since the motor boat is initially at rest)

Acceleration of the motorboat, 

a = 3 m/s²

Time taken, t = 8 s

According to the second equation of motion:

S = ut + 1/2at²

Distance covered by the motorboat, s

S = 0×8 + 1/2×3×8² = 96m__ans

Hence, the boat travels a distance of 96 m.

I think my answer is capable to clear your confusion..
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