A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0 m s-2 for 8.0s how far does the boat travel during this time?
Plzzzzzz... answer
Answers
Answered by
4
u = 0 m/s(rest)
a = 3m/s^2
t = 8 s
first,
v = u+ at
v = 0 + 3*8
v = 24m/s
Now,
s = ut + 1/2at^2
s = 0 + 1/2 * 3*64
s = 96m
plz thnx and mark as brainliest
a = 3m/s^2
t = 8 s
first,
v = u+ at
v = 0 + 3*8
v = 24m/s
Now,
s = ut + 1/2at^2
s = 0 + 1/2 * 3*64
s = 96m
plz thnx and mark as brainliest
Answered by
4
hey friend!!!!!
your answer is "96m"
Explanation =>
____________
Initial velocity, u = 0 (since the motor boat is initially at rest)
Acceleration of the motorboat,
a = 3 m/s²
Time taken, t = 8 s
According to the second equation of motion:
S = ut + 1/2at²
Distance covered by the motorboat, s
S = 0×8 + 1/2×3×8² = 96m__ans
Hence, the boat travels a distance of 96 m.
I think my answer is capable to clear your confusion..
your answer is "96m"
Explanation =>
____________
Initial velocity, u = 0 (since the motor boat is initially at rest)
Acceleration of the motorboat,
a = 3 m/s²
Time taken, t = 8 s
According to the second equation of motion:
S = ut + 1/2at²
Distance covered by the motorboat, s
S = 0×8 + 1/2×3×8² = 96m__ans
Hence, the boat travels a distance of 96 m.
I think my answer is capable to clear your confusion..
Similar questions