Question

A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0m s^-2 for 8.0 s. How far does the boat travel during this time?

Answer 1

Answer:216m

Explanation:using eq:s=ut + 1/2 at²

U=0 ,t=12,a=3m/s²

S=0.t+1/2x 3x12²=216m

Answer 2

GIVEN:

• Initial Velocity (u) = 0
• Acceleration (a) = 3 m/s²
• Time taken (t) = 8 seconds

TO FIND:

• What is the distance covered by the boat in 8 seconds ?

SOLUTION:

Let the distance travelled by the boat be 's' m

To find the distance of the boat, we use the formula:-

$\large\bf{\star \: s = ut + \dfrac{1}{2} at^2 \: \star}$

According to question:-

$\sf{\rightarrow s = 0 \times 8 + \dfrac{1}{2} \times 3 \times (8)^2}$

$\sf{\rightarrow s = 0 + \dfrac{1}{\cancel{2}} \times 3 \times \cancel{8} \times 8}$

$\sf{\rightarrow s = 3 \times 4 \times 8}$

$\bf{\rightarrow \star \: s = 96 \: m \: \star}$

❝ Hence, the distance travelled by the boat is 96 m ❞

______________________

✯ Extra Information ✯

➩ First equation of motion = v = u + at

➩ Third Equation of motion = v² - u² = 2as