Question

a motorboat starting from rest on a lake accerlate in a straight line at a constant rate of 3m per second for 8 s. how far does the travel during this time ​

Answer 1

Answer:

given initial velocity of motorboat,u=0

acceleration of motorboat,a=3 m per sec square

time,t=8 secs

distance,s=ut+( 1/2) at2

therefore the distance traveled by the motorboat =0-8+(1/2)*3*8

=(1/2)*8**8*3

=96 m

Answer 2

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.