Question

A motorboat starting from rest on a lake retains final velocity 3 m/ sec in 8.0 second. How far does the boat travel during this time.​

Answer 1

Answer:

12 m

Explanation:

Given :

Initial velocity u = 0 m / sec

Final velocity v = 3 m / sec

Time t = 8 sec

We are asked to find distance s :

Using third equation of motion :

v² = u² + 2 a s

= > s = ( v² - u² ) / 2 a   [ a = v - u / t ]

= > s = [ ( v - u ) ( v + u ) ] / [ 2 ( v - u ) / t ]

= > s = ( v + u ) t / 2

Putting values here we get :

= > s = ( 3 + 0 ) 8 / 2 m

= > s = 3 ( 4 ) m

= > s = 12 m

Therefore , motorboat distance 12 m distance!

Answer 2

Answer:

12m

Explanation:

A motorboat starting from rest

So,u=0m/s

final velocity 3 m/ sec

So,v=3m/s

8.0 second

So,t=8 sec

s=?

v=u+at

3=0+8a

3=3a

a=3/8 m/s^2

s=ut+at^2/2

s=0(8)+3/8×8×8/2

s=24/2

s=12m

Hope it helps you.

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