Question

a motorboat starting from rest on a Take accelerates in at a constant rate of 3.0 ms for 8.0 s How far does the boat travel during this time

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Answer 1

Answer:

According to the 2nd equation of motion that is

Position time relation

we've to use

$s = ut + \frac{1}{2} {at}^{2}$

here

initial velocity,u=0

time,t=8

Acceleration,a=3

s=0×8+1/2×3×8²

=0+1/2×192

=96

therefore the boat travelled 96m in the time