Question

A motorboat starting from rest ona lake
accelerates in a straight line at a constant
rate of 3 ms 2 for 8g. How far does the boat
travel during this time?​

Answer 1

Answer:

96m

Explanation:

velocity of motorboat (v)=0

acceleration of motorboat (a)=3.0Ms-2

time under consideration (t)=8.0s

distance (s) =v×t+(1/2)at2

Therefore distance traveled by motorboat =0×8+(1/2)3.0×8.2

=(1/2)×3×8×8m

=96m

Answer 2

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.