Question

a motorboat starts from rest and moves with a velocity of 15 metre per second in 5 seconds calculate the acceleration and the distance travelled in the time

Answer 1

Here's the answer

Given => 

Initial velocity = 0 m/s

Final velocity = 15 m/s

Time taken = 5 second


To find =>

Acceleration = ?

Distance travelled = ?

We know that,

Acceleration = v − u / t

= 15 - 0 / 5 

= 3 m/s^2

Now,

By using second kinematical equation,

s = ut + 1/2at^2  

s = 0 + 1/2 × 3 × 5^2

= 75/2

= 37.5m 

Distance covered = 37.5 metre 

Answer 2

Answer:

Acceleration = 3 m/s²

Distance = 37.5 m

Explanation:

u = 0 m/s

v = 15 m/s

t = 5 s

a = (v - u)/t

=> a = (15 - 0)/5

=> a = 15/5

=> a = 3 m/s²

s = ut + ½ at²

=> s = 0 * 5 + ½ * 3 * 5²

=> s = 0 + ½ * 3 * 25

=> s = 75 / 2

=> s = 37.5 m

So,

Acceleration = 3 m/s²

Distance = 37.5 m